Let us find out the size of the column for a total load acting over it. Let us consider the total axial load over the column as 1650KN.
Given data:
Total load over the column = 1650KN. = 1650 x 10³N
To find:
Column size = L x B =?
Calculation:
Factored load = Pu = [1.5 x 1650KN]
Pu = 2475KN. =2475 x 10³N
Let us use M30 grade concrete & Fe415 steel in this column.
As per IS code
Pu = [0.4 x fck x Ac + 0.67 x fy x Asc]
Where,
Pu = Ultimate load considered = 2475 x 10³N
fck = Characteristic compressive strength of concrete = 30 N/mm²
fy = Yield strength of steel = 415 N/mm²
Ac = Sectional area of concrete =?
Asc = Sectional area of steel
Let us provide 1.5% of steel (Asc ) in the column
which means Asc = 1.5% of Ac. = 0.015Ac
Pu = [0.4 x fck x Ac + 0.67 x fy x Asc]
2475 x 10³N = [(0.4 x 30 x Ac )+ (0.67 x 415 x 0.015Ac) ]
2475 x 10³N = [12 Ac + 4.171Ac ]
2475 x 10³N = [16.171 Ac ]
Ac = 2475 x 10³N ➗ 16.171 N/mm²
= 153.05 x 10³ mm²
= 1,53,051mm²
1. Square column:
If we go for a square column
Length( L) = breadth ( B )
The sectional area of the column
Ac = [ L x B ]= L²
L² = 153051mm²
L = √ 153051
= 391.21mm.
The size of the column will be 391.21mm. x 391.21mm.
By rounding off, let us provide a column of size 400mm. x 400mm.
2. Rectangular column:
Practically, in residential buildings, we take the breadth of the columns as 225mm. ( 9" ) to match the width of the wall.
Therefore,
[L x B] = 153051mm²
[L x 225mm.] = 153051mm²
L = [153051mm² ➗ 225mm.]
= 680.2mm.
The size of the rectangular column = 225mm. x 680mm.
OR
If we provide a column having a width of 300mm.(12")
L = [153051mm² ➗ 300mm.]
= 510mm.
The column size = 300mm. x 510mm.
I hope you understood the concept.
Note:
1. This calculation method can be used for general residential buildings.
2. Multi-storeyed building involves several design criteria to calculate the dimensions.
Go through the article 👇
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Thank you for going through these calculation steps❤. Have a good day 😄.
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