Eg:
Calculate the specific wt., density & specific gravity of a one-liter of a liquid weighing 9N.
Calculation:
Given data:
Volume of liquid = V =1 litre.= 0.001m³
Weight of liquid = W = 9N.
To find:
Specific weight or wt. density = w =?
Density = 𝞎 =?
Specific gravity = G =?
1. Specific weight:
w = [weight ÷ volume]
= [9N ÷ 0.001m³]
= 9000N/m³
Specific weight = w = 9000N/m³
2. Density:
w = [𝞎 × g]
Where,
g = acceleration due to gravity = 9.81m/sec²
9000N/m³ = [𝞎 × 9.81]
Therefore 𝞎 = [9000 ÷ 9.81]
= 917.43kg/m³
Density of liquid = 𝞎 = 917.43kg/m³
3. Specific gravity:
G = [density of liquid ÷ density of water]
As you know,
The density of water = 1000kg/m³
Therefore,
G = [917.43 ÷ 1000]
= 0.917
Specific gravity = G =0.917
Thank you for going through these calculation steps❤. Have a good day 😄.
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