Eg:
The following observations were made in a tacheometric surveying. A tacheometer was set up at the intermediate point on line AB.
Multiplying constant (f /i) = 100, additive constant (f +d) = 0.1
Calculate the horizontal distance AB & RL of station B. RL of station A is 465m.
Calculation:
D = (f/i ) S cos²θ + (f +d ) cosθ
Now,
D1 = = (f/i ) S1 cos²θ1 + (f +d ) cosθ1
Here,
S1 = staff intercept at station A = 2.425
θ1 = Vertical angle = 6°30'
D1 = [(100 ✕ 2.425 ✕ cos² 6°30') + ( 0.1 ✕ cos6°30')]
= [239.39 + 0.0993]
D1 = 239.49 m.
Similarly,
D2 = [(100 ✕ 1.950 ✕ cos² 9°15') + ( 0.1 ✕ cos9°15')]
= [189.962 + 0.0987]
D2 = 190.06 m.
The formula for vertical distance
V = [(f/i ) S sin2θ /2 + (f +d ) sinθ]
Now,
V1 = [(f/i ) S1 sin2θ1 /2 + (f +d ) sinθ1]
= [ {100 ✕ 2.425 ✕ sin(2 ✕ 6°30') /2} + (0.1 ✕ sin6°30')]
=[ 27.275 + 0.0113]
V1 = 27.29 m.
Similarly,
V2 = [(f/i ) S2 sin2θ2 /2 + (f +d ) sinθ2]
= [ {100 ✕ 1.95 ✕ sin(2 ✕ 9°15') /2} + (0.1 ✕ sin9°15')]
=[ 30.937 + 0.0161]
V2 = 30.95 m.
RL of a central axis of the instrument at station P
= [RL at station A + axial hair reading of staff at A - V1]
= [ 465m. + 2.150 - 27.29]
= 439.86m.
Find: 👇
1. Horizontal distance AB
= [D1 +D2]
= [239.49m. + 190.06m.]
= 429.55m.
2. RL of station B
= [RL of instrument axis at P + V2 - axial hair reading of staff at B]
= [ 439.86m. + 30.95m. - 1.865]
= 468.945m.
To understand A to Z of surveying, click here.
Thank you for going through these calculation steps❤. Have a good day 😄.
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