Let us solve an example to understand the calculation procedure of interior angles in a closed traverse.
Eg:
The following bearings were noted down with a compass in an anticlockwise traverse. Calculate the interior angles of a closed traverse.
Line |
Fore bearing |
AB |
112°30 ' |
BC |
27°15' |
CD |
276° 0' |
DE |
187°45' |
EA |
118°30' |
Following are the 4 points or rules to be known before computing the interior angles.
1. For the anticlockwise traverse,
Included angle = [fore bearing of next line - back bearing of the previous line.]
2. If a back bearing is >180°, deduct 180° from the bearing.
3. If a back bearing is < 180°, add 180° to the bearing.
4. If the value of included angle comes -ve, we have to add 360° to compute the angle in the whole circle bearing system.
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Calculation:
The closed anticlockwise traverse is drawn for the given fore bearings as below.
For the anticlockwise traverse,
Included angle = [fore bearing of next line - back bearing of the previous line.]
Here, back bearing is not given, so we have to calculate the back bearing with the help of fore bearings.
Note:
BB 👉 short form of back bearing.
FB 👉 short form of fore bearing.
1. Angle A:
∠A = [FB of line AB - BB of line EA]
As fore bearing of EA < 180°, we have to add 180° to the FB.
BB of line EA
= [118°30' + 180° ]
= 298°30'
∠A = [112°30' - 298°30']
= -186°
In the whole circle bearing system, the angle cannot be -ve. In such cases, we have to add 360° to the -ve angle.
∠A = [-186° + 360°]
= 174°
2. Angle B:
∠B = [FB of line BC - BB of line AB]
As fore bearing of AB < 180°, we have to add 180° to the FB.
BB of line A B
= [112°30' + 180° ]
= 292°30'
∠B = [27°15' - 292°30']
= -265°15'
∠B = [-265°15' + 360°]
= 94°45'
3. Angle C:
∠C = [FB of line CD - BB of line BC]
As fore bearing of BC < 180°, we have to add 180° to the FB.
BB of line BC
= [27°15' + 180° ]
= 207°15'
∠C = [276° - 207°15']
= 68°45'
4. Angle D:
∠D = [FB of line DE - BB of line CD]
As fore bearing of CD > 180°, we have to deduct 180° from the FB.
BB of line CD
= [276° - 180° ]
= 96°
∠D = [187°45' - 96°]
= 91°45'
5. Angle E:
∠E = [FB of line EA - BB of line DE]
As fore bearing of DE > 180°, we have to deduct 180° from the FB.
BB of line DE
= [187°45' - 180° ]
= 7°45'
∠E = [118°30' - 7°45']
= 110°45'
Go through the article 👇
👀. Calculating RL by rise & fall method.
Check:
The total sum of interior angles
= [∠A +∠B + ∠C +∠D + ∠E]
= [174° + 94°45' + 68°45' + 91°45' + 110°45']
= 540°
The total value of the angle should be equal to [(2n -4) ✕90°], where n= no. of sides.
[(2 ✕ 5 - 4) ✕ 90°] = [6 ✕ 90°] = 540° ✔
Go through the article 👇
👀. Finding bearings from included angles in compass surveying.
Thank you for going through these calculation steps❤. Have a good day 😄.
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