Let us now calculate the volume of concrete in a rectangular pile foundation having 6 nos. of the pile, as shown below.
Given data:
Pile diameter = 60 cm = 0.6m.( d )
No. of piles = 6 nos.
Length of pile = 18m. (h )
Size of the pile cap = 4.5m ( L ) × 3.0m. (B )
Depth of the pile cap = 0.9m.(H )
The volume of concrete in a pile cap
= L × B × H
= 4.5m × 3.0m × 0.9m
= 12.15 cum.
The volume of concrete in the piles
= 6nos.× πr2 h
Here,
r = radius of the pile.
= d ÷ 2
= 0.6m ÷ 2
= 0.3m.
h = length of the pile.
The volume of concrete in piles
= 6nos. × 3.142 × (0.3m)2 × 19m.
= 32.23 cum.
The total concrete volume of the pile foundation
= The vol. of concrete in pile cap + total vol. of concrete in piles.
= 12.15 cum + 32.23 cum.
= 44.38 cum.
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