Let us calculate the volume of concrete in a triangular pile foundation having 3 nos. of the pile, as shown below.
Given data:
Pile diameter = 0.6m.( d )
No. of piles = 3 nos.
Length of pile = 16m. (h )
Depth of the pile cap = 0.9m. (D )
Calculation:
The volume of concrete in the piles
= [3nos.× πr2 h]
Here,
r = radius of the pile.
= [d ÷ 2]
= [0.6m ÷ 2]
r = 0.3m.
h = length of the pile.
The volume of concrete in piles
= [3nos. × 3.142 × (0.3m)2 × 16m.]
= 13.57 cum.
The volume of concrete in the pile cap :
The volume of pile cap concrete
= [Surface area (A ) × depth ( D )]
First, let us calculate the sectional area (A1) of rectangle ABCD, as shown in the below drawing.
Area of rectangle ABCD (A1)
= [L × B]
= [2.2m × 2.0m]
= 4.4 sqm.
To get the surface area ( A) of the pile cap, we have to deduct the area of triangles AEF & GDH from the rectangle area.
Here,
Triangle AEF = triangle GDH
Area of triangle AEF
= [0.5 × base × height.]
= [0.5 × side AE × side AF]
Side AE
= [ ( 1/2 ×side BC ) - (1/2 × side EG )]
= [ ( 1/2 ×2m. ) - (1/2 × 0.6m. )]
= [ 1m - 0.3 m ]
= 0.7m.
Side AF
= [side AB - side FB]
= [2.2m - 0.7m]
= 1.5m.
I have redrawn the triangle, with the calculated length of the sides AF & AE as shown below.
= [0.5 × side AE × side AF]
= [0.5 × 0.7m × 1.5m.]
= 0.525 sqm.
The surface area of the pile cap (A )
= [area of rectangle ABCD - (2nos. × area of a triangle AEF )]
= [4.4 sqm. - (2nos. × 0.525sqm.)]
= [4.4 sqm. - 1.05 sqm.]
= 3.35 sqm.
Now,
the concrete vol. of pile cap
= [surface area (A ) × depth (D )]
= [3.35 sqm. × 0.9m.]
= 3.015 cum.
The total concrete volume of the 3-pile foundation
= [The vol. of concrete in pile cap + total vol. of concrete in piles.]
= [3.015 cum + 13.57 cum.]
= 16.585 cum.
To go through the articles on Estimation & calculation in civil engineering, click here.
Thank you for going through these calculation steps❤. Have a good day 😄.
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