The chair bars are placed in the footings to support the top and bottom reinforcement cage as shown below.
The cutting length of the chair bar
= [{(2nos.× height ) + (1no. × head ) + ( 2nos. × leg)} - (4nos. × 90° bend )]
Given data:
The diameter of the chair bar = d =12mm.
Top & bottom clear cover = 50mm.
Depth of footing = 750mm.
Top & bottom main bar dia. = 20mm, spacing @ 150c/c.
Top & bottom distribution bar dia. = 16mm, spacing @ 150 c/c.
Now, we will calculate the length of the three parts of the chair bar separately.
1. Head ( E ):
The length of the head
= [(2nos.× c/c distance between the top distribution bar) + (extra length on either side of the top distribution bar)]
= [( 2nos. × 150mm. ) + ( 2nos. × 50mm. )]
{ Here, 50mm. is taken as the extra length. }
= [ ( 300mm. + 100mm. ]
= 400mm.
2. Height (H ):
Height of the chair
= [(footing depth ) - {(2nos. × clear cover ) + ( dia. of top main bar + dia. of top distribution bar + dia. of bottom main bar)}]
= [(750mm ) - {( 2nos. × 50mm.) + ( 20mm + 16mm + 20mm )}]
= [750mm - { 100mm + 56mm }]
= [ 750mm - 156mm ]
= 594mm.
3. Leg ( L ):
The length of the leg
= [(2nos.× c/c distance between the bottom main bar) + (extra length on either side of the bottom main bar)]
= [( 2nos. × 150mm. ) + ( 2nos. × 50mm. )]
{ Here, 50mm. is taken as the extra length. }
= [ ( 300mm + 100mm. ]
= 400mm.
The cutting length of the chair bar
= [ 2H + E + 2L - 8d ]
= [{(2nos.× height ) + (1no. × head ) + ( 2nos. × leg)} - (4nos. × 90° bend )]
= [{(2nos. × 594mm. ) + ( 1no. × 400mm.) + ( 2nos. × 400mm. )} - ( 4nos. × 2d )]
{Here, 2d is taken for the 90° bend, where d is the dia. of chair bar.}
= [ {1188mm. + 400mm. + 800mm.} -( 4nos. × 2 × 12mm )]
= [ 2388mm - 96mm ]
= 2292mm.
2. For the general calculation purpose 50mm. is taken as the extra length.
For BBS & cutting length of all types of structural members, click here.
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