Let us make coping over block masonry having 4" (0.33 ft.) thickness in M15 grade.
8. The volume of coping for the compound wall
= coping length × width × thickness
= block masonry length × masonry width × coping thickness
= 119.5 ft. × 0.5 ft. × 0.33 ft.
= 19.717 cu ft. i.e. 0.558 cu m.
Let us make this coping in M15 grade concrete.
The no. of cement bags required for the coping work
=17.942 bags × (19.717 ÷ 100 cu ft. )
= 3.537 bags.
The volume of sand required for coping
= 44 cu ft × (19.717 ÷ 100 cu ft. )
= 8.675 cu ft.
The volume of coarse aggregates required
= 88 cu ft. × (19.717 ÷ 100 cu ft. )
= 17.35 cu ft.
Note: The above value for the calculation purpose is taken from " Calculating the quantity of materials in 100 cu ft. & 1 cum. of M15 (1:2:4 ) grade concrete".
9. The volume of backfilling for the compound wall
Backfilling for plinth beam
= Volume of excavation for plinth beam. - beam PCC volume - plinth beam volume up to GL.
= [(145.365 cu ft.) - (52.33 cu ft.) - (97.125cu ft. × 0.583ft ÷ 1 ft.)
( By volume ratio with plinth beam 👆)
= 145.365 cu ft. - 52.33 cu ft - 56.623 cu ft.
= 36.412 cu ft.
Backfilling for footing.
=[ volume of excavation for footing - {footing vol. - soling vol. - PCC vol. - column vol. up to GL.}]
= [140 cu ft.- {26.24 cu ft. + 42 cu ft. + 18.48 cu ft.+ ( 14 nos × 0.583 × 0.75 × 0.75) } ]
= [140 cu ft - 91.31 cu ft.]
=48.69 cu ft.
The total volume of backfilling
= backfilling for plinth beam + backfilling for footing
= 36.412 cu ft. + 48.69 cu ft.
= 85.102 cu ft. i.e. 2.409 cum.
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