Let us consider a land of size 50ft. × 80 ft., that should be fenced using RCC poles and barbed wires.
Here, L = 80 ft. & B = 50 ft.
We will consider purchasing an RCC fence pole of size 6 ft.× 4 inches × 4 inches and 12 gauge barbed wire to complete this work.
Let us install this fencing pole at 8 ft. c/c distance as shown in fig. below.
First, we will calculate the number of poles required to cover this land.
Number of poles on the longer sides of the land
= 2 sides ×(( length of the land ÷ c/c distance between the poles)
=2 × ( 80 ft. ÷ 8 ft.)
= 2 × 10
= 20 nos.
Similarly, the number of poles on the shorter side of the land
= 2 sides × (( width of the land ÷ c/c distance between the poles)
=2 × (( 50 ft. ÷ 8 ft.)
= 2 ×( 6.25 )
= 12.5 nos.
By rounding up the no. of poles.
= 12 nos.
When we divide 50 ft. by 8 ft., the remainder will be 2 ft. So instead of taking extra poles, we can distribute this extra distance between these 6 poles of each side.
C/C distance of poles on the shorter side
= 50ft.÷ 6 ft.
= 8.33 ft. ( as you can see in the above fig.)
We need 2 poles at all 4 corners of the land to support the end poles from bending due to wire tension.
So, the number of poles = 2nos. × 4 corners
= 8 nos.
Total number of poles required
= on the length side + on the width side + supporting poles
= 20 nos.+ 12 nos. + 8 nos.
= 40 nos.
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