Let us consider an MS square bar of size 20mm × 20mm having 3m. length.
The weight of the MS square bar is calculated by the formula,
= [d2L / 127.39]
Here,
d = 20mm. & L = 3m.
Weight of the bar
= [20mm × 20mm ×3m / 127.39]
= 9.42 kg.
Note: In this formula, the sectional dimension should be in millimeters & the length should be in meters.
 |
| MS square bar. |
So, you can calculate the weight of the MS square bars of any dimension by using this formula.
Now the question is,
How the formula d2L / 127.39 is derived for the MS square bar?
Let us consider a square bar of sectional dimension d in mm having the length L as shown below.
As you know, in square bars, all 4 cross-sectional sides are equal.
The volume of the MS square bar
= [breadth × depth × length]
= [(d × 0.001) m. × ( d × 0.001) m. × L m.]
(1mm = 0.001m. and we have converted all dimensions into the same unit i.e. meter.)
= 0.000001 d2L cum.
Now,
the weight of the MS bar
= [volume × density]
= [0.000001 d2L cum × 7850 kg/ cum]
= 0.00785 d2L kg
OR
By inverse,
Weight of the MS square bar
= d2L / 127.39 kg.
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